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Kulhad Chai: Next time you have kulhad chai, don’t miss the bubbly physics

2023年12月13日

The HinduAdhip Agarwala

A fluid a specific gravity of 0.83 and a kinematic viscosity of... | Filo

A fluid a specific gravity of 0.83 and a kinematic viscosity of... | Filo

Knowing the viscosity coefficient of helium under standard cond... | Filo

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SOLVED:Some experimental data for the viscosity of helium at 1 atm are T,^∘𝐂 0 100 200 300 400 μ, 𝐍·𝐬 / 𝐦^2(×1 0^5) 1.86 2.31 2.72 3.11 3.46 Using the approach described in Appendix A.3, correlate these data to the empirical Sutherland equation μ=(b T^1 / 2)/(1 S / T) (where T is in kelvin) and obtain values for constants b and S.

SOLVED:Some experimental data for the viscosity of helium at 1 atm are T,^∘𝐂 0 100 200 300 400 μ, 𝐍·𝐬 / 𝐦^2(×1 0^5) 1.86 2.31 2.72 3.11 3.46 Using the approach described in Appendix A.3, correlate these data to the empirical Sutherland equation μ=(b T^1 / 2)/(1 S / T) (where T is in kelvin) and obtain values for constants b and S.

2020年6月12日

SOLVED:Experimental values for the viscosity of helium at 1 atm are as follows: T, K 200 400 600 800 1000 1200 μ, kg /(m·s) 1.50 E-5 2.43 E-5 3.20 E-5 3.88 E-5 4.50 E-5 5.08 E-5 Fit these values to either (a) a power law or (b) the Sutherland law, Eq. (1.30).

SOLVED:Experimental values for the viscosity of helium at 1 atm are as follows: T, K 200 400 600 800 1000 1200 μ, kg /(m·s) 1.50 E-5 2.43 E-5 3.20 E-5 3.88 E-5 4.50 E-5 5.08 E-5 Fit these values to either (a) a power law or (b) the Sutherland law, Eq. (1.30).

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