Calculating phase difference - The Student Room
2023年6月23日 · Ryen. 1. 0.4 divided by the wavelength (1.2) so you get the phase difference. To get that answer in radian multiply it by 2 pi. Reply 12. 4 years ago. Divya shree. 1. The formula for phase difference = K • delta x Since k = 2 pie / lemda Substituting the value of lemda = 1.2 We get k = 2 pie / 1.2 ,And delta x = 0.4 Hence solving , k ...
Isaac physics problem about phase and path difference D3.19
Calculate the phase difference as it would be detected by the person. And the speed of sound in air is given as 330m/s I worked out the wavelength as 330/256=165/128 Phase difference = ( path difference / wavelength ) (2pi or 360) = ( 0.5 / (165/128) ) (2pi or 360) giving me a phase difference of 2.4 radians or 140 degrees to 2 sf Isaac physics ...
calculating the phase difference from oscillations
2024年6月17日 · If you have two traces of the same form (e.g. sinusoidal) and same frequency then the phase difference is the distance between a point on one and the corresponding point on the other, as I think you're describing. A good example are the sin and cos graphs. cos(0) = 0 and sin(90) = 0, therefore the sin graph is simply the cos graph with a phase ...
Path difference? question - The Student Room
2018年5月9日 · 6. Two aerials are 2.50m apart, and both are receiving the same radio signal with a frequency of 125MHz. The phase difference between them is measured as 114∘. Calculate the path difference between the two aerials. The aerial which receives the radio signal first is directly North of the one which receives the signal slightly later.
Physics Interference Question Help - The Student Room
4. Here is the original question and the first part: Two speakers are set up 13.5m apart in an auditorium, pointing at each other. A pure sound of frequency 256Hz is being played through them. You may assume that the phase difference of the signals as they arrive at the speakers is 0∘. A person is standing on the line joining the speakers, 0 ...
Phase difference - The Student Room
The phase of a wave is a point on the wave cycle. Two points on a wave are "in phase" if they're a whole number of cycles apart. If two points on a wave are not in phase, there will be a phase difference between them. The phase difference is the fraction of the cycle that separates the points. With that knowledge can you work out the phase ...
Physics Homework, please help - The Student Room
2016年10月28日 · Physics Homework, please help. Two ariels are 2.50m apart, and both are receiving the same radio signal with a frequency of 125 MHz. The phase difference between themis measured at 114 degrees. Calculate the path difference between the two ariels. The ariel in the previous question which recieves the signal first is directly North of one which ...
Isaac physics Path difference help! - The Student Room
It is required that the maximum phase difference thus caused is no more than 30 degrees. Calculate the maximum path difference allowed. Could someone please help me out with the steps showing how you got the answer? Path diff= (wavelength x phase diff)/360. Therefore, path diff = (1.5x10^-6 x 30)/360 = 1.25x10^-7m or 125nm.
wavelength problem . need an explanation - The Student Room
2015年2月4日 · The OC and AB pairs are in phase (0 o): Both points are between the same nodes or there are an even number of nodes between the points. OA, OB, AC and BC pairs are out of phase (pi/2 or 180 o): The points are immediately either side of a single node or there are an odd number of nodes between the points.
Mcq prob. Phase difference - The Student Room
2018年4月9日 · Path difference Δ x \Delta x Δ x and phase difference ϕ \phi ϕ is linked by the following equation: ϕ 2 π = Δ x λ \dfrac{\phi}{2 \pi} = \dfrac{ \Delta x }{ \lambda} 2 π ϕ = λ Δ x We can ignore the phase difference due to the reflection and make sure you know why.